Answer
$\displaystyle \left\{x\ |\ \frac{2}{3}\leq x\leq 3\right\}$ or $\displaystyle \left[\frac{2}{3},3\right]$
Work Step by Step
$-5\leq 4-3x\leq 2\qquad$ ... subtract 4
$-9\leq-3x\leq-2\qquad$ ... divide with -3 (negative)
... the inequalities change direction....
$3\displaystyle \geq x\geq\frac{2}{3}$
Solution set: $\displaystyle \left\{x\ |\ \frac{2}{3}\leq x\leq 3\right\}$ or $\displaystyle \left[\frac{2}{3},3\right]$
