Answer
$a=4$ and $b=16$
Work Step by Step
We are given:
$6\lt 3x\lt 12$
We divide by $3$:
$\frac{6}{3}\lt \frac{3x}{3}\lt \frac{12}{3}$
$2\lt x\lt 4$
We take the square:
$2^{2}\lt x^{2}\lt 4^{2}$
$4\lt x^{2}\lt 16$
Therefore:
$a=4$ and $b=16$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.5 - Solving Inequalities - 1.5 Assess Your Understanding - Page 128: 101
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