Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set: 6

Answer

y=$\frac{2}{3}$x+10

Work Step by Step

slope $\frac{2}{3}$ , through (-9;4) y-$y_{1}$=m(x-$x_{1}$) y-4=$\frac{2}{3}$(x+9) y-4=$\frac{2}{3}$x+6 y=$\frac{2}{3}$x+6+4 y=$\frac{2}{3}$x+10
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.