Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set - Page 572: 18

Answer

$4x - 4y = 3$

Work Step by Step

$(y - y_{1})\div(y_{2} - y_{1}) = (x - x_{1})\div(x_{2} - x_{1})$ Substitute all of the variables in, getting $ (y + \frac{1}{4}) \div (\frac{3}{4} + \frac{1}{4}) = (x -\frac{1}{2}) \div (\frac{3}{2} - \frac{1}{2})$ $ y + \frac{1}{4} = x - \frac{1}{2}$ Subtract $y$ from both sides $\frac{1}{4} = x - y - \frac{1}{2}$ Add $\frac{1}{2}$ to both sides $\frac{3}{4} = x - y $ $ 4x -4y = 3$
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