Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set: 16

Answer

y+3=$\frac{5}{4}$(x-8) $\frac{5}{4}$x-y=13

Work Step by Step

(8;-3),(4,-8) m=$\frac{-8+3}{4-8}$=$\frac{-5}{-4}$=$\frac{5}{4}$ slope $\frac{5}{4}$ ,through(8;-3) y-$y_{1}$=m(x-$x_{1}$) y+3=$\frac{5}{4}$(x-8) y+3=$\frac{5}{4}$x-10 3+10=$\frac{5}{4}$x-y 13=$\frac{5}{4}$x-y
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.