Answer
LCD=(2)(3)(x+1)(x+1)=6$(x+1)^{2}$
Work Step by Step
$\frac{1}{3x+3}$, $\frac{8}{2x^{2}+4x+2}$
2$x^{2}$+4x+2=2$x^{2}$+2x+2x+2=2x(x+1)+2(x+1)=
=(2x+2)(x+1)=2(x+1)(x+1)
3x+3=3(x+1)
LCD=(2)(3)(x+1)(x+1)=6$(x+1)^{2}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set - Page 508: 25
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