Answer
LCD=(x-1)(x+1)(2x+1)(3x+1)
Work Step by Step
$\frac{2x}{3x^{2}+4x+1}$, $\frac{7}{2x^{2}-x-1}$
3$x^{2}$+4x+1=3$x^{2}$+x+3x+1=x(3x+1)+1(3x+1)=(x+1)(3x+1)
2$x^{2}$-x-1=2$x^{2}$+x-2x-1=x(2x+1)-1(2x+1)=(x-1)(2x+1)
LCD=(x-1)(x+1)(2x+1)(3x+1)
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set - Page 508: 31
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