Answer
$\frac{x(x+1)}{(x)(x+2)(x+4)(x+1)}$
Work Step by Step
$\frac{x}{x^3+6x^2+8x}$
$x^3+6x^2+8x$
$x(x^2+6x+8)$
$x(x+2)(x+4)$
$\frac{x}{x^3+6x^2+8x} = \frac{x}{(x)(x+2)(x+4)}$
$\frac{x}{(x)(x+2)(x+4)}=\frac{x*(x+1)}{(x)(x+2)(x+4)*(x+1)}$
$\frac{x(x+1)}{(x)(x+2)(x+4)(x+1)}$