Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Exercise Set: 87

Answer

$\frac{2y^{8}}{3}$

Work Step by Step

$\frac{2x^{4}y^{12}}{3x^{4}y^{4}}=\frac{2x^{4-4}y^{12-4}}{3}=\frac{2x^{0}y^{8}}{3}=\frac{2(1)y^{8}}{3}= \frac{2y^{8}}{3}$
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