Answer
$\frac{-3b^{3}}{2}$
Work Step by Step
$\frac{-48ab^{6}}{32ab^{3}}=\frac{-48a^{1-1}b^{6-3}}{32}=\frac{-48a^{0}b^{3}}{32}=\frac{-48(1)b^{3}}{32}= \frac{-3b^{3}}{2}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.