## Algebra: A Combined Approach (4th Edition)

Answer: $4x^{2}+4x+1$
$(2x+1)^{2}$ Take any number, say $'a'$ . For squaring that number: $a^{2}$, we multiply that number by itself: $a^{2}$ = $a\times a$ Thus, here the number is $(2x+1)$. Thus, $(2x+1)^{2}$ = $(2x+1)\times (2x+1)$ =$2x(2x+1)+1(2x+1)$ =$4x^{2}+2x+2x+1$ =$4x^{2}+4x+1$