# Chapter 5 - Section 5.2 - Negative Exponents and Scientiﬁc Notation - Exercise Set: 124

-2

#### Work Step by Step

We know that $a^{-n}=\frac{1}{a^{n}}$ (where $a$ is a real number and $n$ is a positive integer). Therefore, $\frac{1}{49}=\frac{1}{7\times7}=\frac{1}{7^{2}}=7^{-2}$.

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