Answer
$9a^{13}$
Work Step by Step
$(2a^{3})^{3}a^{4}+a^{5}a^{8}=2^{3}a^{3\times3}a^{4}+a^{5}a^{8}=8a^{9}a^{4}+a^{5}a^{8}=8a^{9+4}+a^{5+8}=8a^{13}+a^{13}=9a^{13}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 356: 121
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