Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set - Page 300: 17

Answer

No solution

Work Step by Step

1. Solve the second equation for x: -2x = y + 4 x = $\frac{y + 4}{-2}$ 2. Substitute x into the first equation: 4($\frac{y + 4}{-2}$) + 2y = 5 3. Solve for y. -2(y + 4) + 2y = 5 -2y - 8 + 2y = 5 -8 = 5 This equation is false, so there is no solution to the system of equations.
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