Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 14

Answer

x = 3 y = 4

Work Step by Step

2x +3y = 18 x = 2y - 5 Substitute x for 2y - 5 to the first equation 2 ( 2y - 5 ) + 3y = 18 4y - 10 + 3y = 18 use the distributive property 7y - 10 = 18 simplify 7y - 10 + 10 = 18 + 10 add 10 to both sides 7y = 28 $\frac{7y}{7}$ = $\frac{28}{7}$ divide both sides by 7 y = 4 x = $2\times4$ - 5 substitude y = 4 to the second equation x = 8 - 5 x = 3
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