Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 19

Answer

x = 3 y = -1

Work Step by Step

4x + y = 11 2x + 5y = 1 to the first equation minus 4x to both sides 4x + y - 4x = 11 - 4x y = 11 - 4x substitude y = 11 - 4x to the second equation 2x + 5 ( 11 - 4x ) = 1 2x + 55 - 20x = 1 use the distributive property - 18x + 55 = 1 - 18x + 55 - 55 = 1 - 55 minus 55 to both sides - 18x = - 54 divide both sides by - 18 x = 3 substitude x = 3 to the y = 11 - 4x y = 11 - $4\times 3$ y = 11 - 12 y = -1
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