Answer
$x=\dfrac{3}{2}$
Work Step by Step
$9^{x}=27$
Rewrite $9$ as $3^{2}$ and $27$ as $3^{3}$:
$(3^{2})^{x}=3^{3}$
On the left side of the equation, multiply both exponents:
$3^{2x}=3^{3}$
If $3^{2x}=3^{3}$, then $2x=3$
$2x=3$
Solve for $x$:
$x=\dfrac{3}{2}$
