Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.3 - Exponential Functions - Exercise Set: 27

Answer

$x=-\dfrac{2}{3}$

Work Step by Step

$\dfrac{1}{4}=2^{3x}$ Rewrite $4$ as $2^{2}$: $\dfrac{1}{2^{2}}=2^{3x}$ Take $2^{2}$ to the numerator by changing the sign of its exponent: $2^{-2}=2^{3x}$ If $2^{-2}=2^{3x}$, then $3x=-2$ $3x=-2$ Solve for $x$: $x=-\dfrac{2}{3}$
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