Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.3 - Exponential Functions - Exercise Set: 28

Answer

$x=-\dfrac{3}{2}$

Work Step by Step

$\dfrac{1}{27}=3^{2x}$ Rewrite $27$ as $3^{3}$: $\dfrac{1}{3^{3}}=3^{2x}$ Take $3^{3}$ to the numerator by changing the sign of its exponent: $3^{-3}=3^{2x}$ If $3^{-3}=3^{2x}$, then $2x=-3$ $2x=-3$ Solve for $x$: $x=-\dfrac{3}{2}$
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