Answer
$f(x)=x^2+3$
$g(x)=3x+4$
Work Step by Step
$h(x)=(3x+4)^2+3$
Let
$g(x)=3x+4$ and
$f(x)=x^2+3$. Then
$(f \circ g)(x)=(g(x))^2+3 = (3x+4)^2 + 3$.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 843: 34
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