Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set: 30

Answer

$F(x)=x+2=(h \circ g)(x)$

Work Step by Step

$F(x)=x+2$ $g(x)=\sqrt x$ $h(x)=x^2+2$. So $F(x)=(g(x))^2+2=h(g(x))=(h \circ g)(x)$.
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