Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set: 25

Answer

$H(x)=\sqrt {x^2+2}=(g \circ h)(x)$

Work Step by Step

$h(x)=x^2+2$ $g(x)=\sqrt x$ $H(x)=\sqrt {x^2+2}$. So $H(x)=\sqrt {h(x)}=g(h(x))=(g \circ h)(x)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.