Answer
$x=-1/2, 1/3$
Work Step by Step
$x^{-2}-x^{-1}-6=0$
$1/{x^2}-1/x-6=0$
$1*x^2/{x^2}-1*x^2/x-6*x^2=0*x^2$
$1-x-6x^2=0$
$-6x^2-x+1=0$
$x=(-b±\sqrt {b^2-4ac})/2a$
$x=(-(-1)±\sqrt {(-1)^2-4*(-6)*1})/2(-6)$
$x=(1±\sqrt {1+24})/-12$
$x=(1±\sqrt {25})/-12$
$x=(1±5)/-12$
$x=(1±5)/-12$
$x=(1+5)/-12$
$x=6/-12$
$x=-1/2$
$x=(1±5)/-12$
$x=(1-5)/-12$
$x=-4/-12$
$x=1/3$