Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 790: 66

Answer

12 inches by 12 inches

Work Step by Step

$(x-4)(x-4)*2=128$ $x*x+x*(-4)+x*(-4)+(-4)(-4)=64$ $x^2-8x+16=64$ $x^2-8x-48=0$ $(x-12)(x+4)=0$ $x-12=0$ $x=12$ $x+4=0$ $x=-4$ (we are talking about dimensions, so this answer is not valid) $x=12$ $(x-4)(x-4)*2=128$ $(12-4)(12-4)*2=128$ $8*8*2=128$ $64*2=128$ (true)
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