Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 787: 28

Answer

$x=-125/8, -27/8$

Work Step by Step

$4x^{2/3}+16x^{1/3}=-15$ $4(x^{1/3})^2+16x^{1/3}=-15$ $x^{1/3}=y$ $4(x^{1/3})^2+16x^{1/3}=-15$ $4y^2+16y=-15$ $4y^2+16y+15=-15+15$ $4y^2+16y+15=0$ $y=(-b±\sqrt {b^2-4ac})/2a$ $y=(-16±\sqrt {16^2-4*4*15})/2*4$ $y=(-16±\sqrt {256-240})/8$ $y=(-16±\sqrt {16})/8$ $y=(-16±4)/8$ $y=(-16±4)/8$ $y=(-16+4)/8$ $y=-12/8$ $y=-3/2$ $y=(-16±4)/8$ $y=(-16-4)/8$ $y=-20/8$ $y=-5/2$ $x^{1/3}=y$ $x^{1/3}=-3/2$ $(x^{1/3})^3=(-3/2)^3$ $x=-27/8$ $x^{1/3}=-5/2$ $(x^{1/3})^3=(-5/2)^3$ $x=-125/8$
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