Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 787: 26

Answer

$x=-15/2, -1$

Work Step by Step

$2-\frac{7}{x+6}=\frac{15}{(x+6)^2}$ $(x+6)^2*2-(x+6)^2*\frac{7}{x+6}=(x+6)^2*\frac{15}{(x+6)^2}$ $(x*x+6*x+x*6+6*6)*2-(x+6)*7=15$ $(x^2+12x+36)*2-(7x+42)=15$ $2x^2+24x+72-7x-42=15$ $2x^2+17x+30=15$ $2x^2+17x+15=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-17±\sqrt {17^2-4*2*15})/2*2$ $x=(-17±\sqrt {289-120})/4$ $x=(-17±\sqrt {169})/4$ $x=(-17±13)/4$ $x=(-17±13)/4$ $x=(-17+13)/4$ $x=-4/4$ $x=-1$ $x=(-17±13)/4$ $x=(-17-13)/4$ $x=(-30)/4$ $x=-15/2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.