Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 787: 20

Answer

$x=-1$

Work Step by Step

$x^{2/3}+2x^{1/3}+1=0$ $(x^{1/3})^2+2x^{1/3}+1=0$ $x^{1/3}=y$ $(x^{1/3})^2+2x^{1/3}+1=0$ $y^2+2y+1=0$ $(y+1)(y+1)=0$ $y+1=0$ $y=-1$ $x^{1/3}=y$ $x^{1/3}=-1$ $(x^{1/3})^3=(-1)^3$ $x=-1$
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