Answer
$a^{4}b^{6}$
Work Step by Step
$(\frac{b^{\frac{3}{4}}}{a^{-\frac{1}{2}}})^{8}$=$\frac{(b^{\frac{3}{4}})^{8}}{(a^{-\frac{1}{2}})^{8}}$=$\frac{b^{3\times2}}{a^{-4}}$=$a^{4}b^{6}$
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