Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 46

Answer

$\frac{y^{2}}{x}$

Work Step by Step

$(x^{-3}y^{6})^{\frac{1}{3}}$ =$(x^{-3})^{\frac{1}{3}}\times (y^{6})^{\frac{1}{3}}$ =$x^{-1}\times y^{2}$ =$\frac{y^{2}}{x}$
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