Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 746: 11

Answer

$2ab^{2}$

Work Step by Step

$\sqrt[5] {32a^{5}b^{10}}$ =$\sqrt[5] {32}\times \sqrt[5] {a^{5}}\times \sqrt[5] {b^{10}}$ =$\sqrt[5] {2^{5}}\times \sqrt[5] {a^{5}}\times \sqrt[5] {b^{10}}$ =$2\times a \times b^{2}$ =$2ab^{2}$
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