Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.5 - Generalized Permutations and Combinations - Exercises - Page 433: 26

Answer

420

Work Step by Step

Set any digit of the number to be 9. We are left with 5 more digits whose sum is equal to 4 So We have $x_{1}+x_{2}+x_{3}+x_{4}+x_{5}$ = 4 We have n=5 and r=4 The solution of this is given by $C$(8,4)=70 Because any of the six digits can be 9 we multiply the above solution by 6. 70$\times$6= 420
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