Answer
$\frac{52!}{13!^{4}}$ = 53,644,737,765,488,792,839,237,440,000
Work Step by Step
Each player will receive 13 cards
Here n=52
k=4
$n_{1}$=13
$n_{2}$=13
$n_{3}$=13
$n_{4}$=13
Distributing n distinguishable objects into k distinguishable boxes such that $n_{i}$ objects are there in each box can be done in $\frac{n!}{x_{1}!....x_{k}!}$ ways.
In our case $\frac{52!}{13!^{4}}$ = 53,644,737,765,488,792,839,237,440,000
