Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.5 - Generalized Permutations and Combinations - Exercises - Page 433: 34

Answer

370

Work Step by Step

Using all seven letters = $\frac{7!}{3!.3!.1!}$ = 140 Using six letters we get a total of 20 + 60 + 60 = 140 3 O's and 3 S's = $\frac{6!}{3!.3!}$ = 20 3 O's , 2 S's and 1 R = $\frac{6!}{3!.2!.1!}$ = 60 2 O's , 3 S's and 1 R = $\frac{6!}{3!.2!.1!}$ = 60 Using five letters we get a total of 10 + 10 + 20 + 20 + 30 = 90 3 O's and 2 S's = $\frac{5!}{3!.2!}$ = 10 2 O's and 3 S's = $\frac{5!}{3!.2!}$ = 10 3 O's, 1 S and 1 R = $\frac{5!}{3!.1!.1!}$ = 20 3 S's, 1 O and 1 R = $\frac{5!}{3!.1!.1!}$ = 20 2'O , 2'S and 1 R = $\frac{5!}{2!.2!.1!}$ = 30 Total strings with five or more characters = 140 + 140 + 90 = 370
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