Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 2 - Section 2.2 - Set Operations - Exercises - Page 136: 21

Answer

See step by step answer for proof.

Work Step by Step

To proof- $ A \cup (B \cup C)=(A \cup B) \cup C$ Proof-$ A \cup (B \cup C)$={$x|x \in A \cup (B \cup C)$} Using the definition of union, an element of $ A \cup (B \cup C)$ is an element of $A$ or an element of $(B \cup C)$ ={$x|x \in A \lor x \in (B \cup C)$} Using the definition of union, an element of $(B \cup C)$ is an element that is in $B$ or in $C$. ={$x|x \in A \lor (x \in B \lor x \in C)$} Using the associative law: ={$x|(x \in A \lor x \in B) \lor x \in C$} Using the definition of union: ={$x|x \in (A \cup B) \lor (x \in C)$} Use the definition of union again: ={$x|x \in (A \cup B) \cup C$} =$(A \cup B) \cup C$ Thus we have shown that $A \cup (B \cup C)$=$(A \cup B) \cup C$
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