Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 2 - Section 2.2 - Set Operations - Exercises - Page 136: 22

Answer

See step by step work for proof.

Work Step by Step

To prove- $A \cap (B \cap C)=(A \cap B) \cap C$ Proof- $A \cap (B \cap C)$={$x|x \in A \cap (B \cap C)$ Using the definition of intersection, an element of $A \cap (B \cap C)$ is an element that is in $A$ and in $B \cap C$ ={$x|x \in A \land x \in B \cap C$} Using the definition of intersection, an element of $B \cap C$ is an element that is in $B$ and in $C$. ={$x|x \in A \land (x \in B \land x \in C)$} Using the associative law for propositions: ={$x|(x \in A \land x \in B) \land x \in C$} Use the definition of intersection: ={$x|x \in (A \cap B) \land x \in C$} Use the definition of intersection again: ={$x|x \in (A \cap B) \cap C$} =$(A \cap B) \cap C$ Thus, we have shown that $(A \cap B) \cap C$=$A \cap (B \cap C)$
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