University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 33 - The Nature and Propagation of Light - Problems - Exercises - Page 1106: 33.29

Answer

a. 1.40. b. $35.5^{\circ}$.

Work Step by Step

The sunlight strikes the glass at Brewster’s angle (the polarizing angle) because we know the reflected light is completely polarized. Equation 33.8 tells us $tan \theta_p=\frac{n_b}{n_a}$. $$tan 54.5^{\circ}=\frac{n_{glass}}{1.00}$$ $$n_{glass}=1.40$$ b. Use Snell’s Law, where the angles are measured from the normal to the interface. $$n_a sin\theta_a= n_b sin\theta_b$$ $$\theta_b=sin^{-1}(\frac{n_a}{n_b}sin\theta_1) $$ $$=sin^{-1}(\frac{1.00}{1.40}sin54.5^{\circ}) =35.5^{\circ}$$
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