Answer
See explanation.
Work Step by Step
a. $v=\frac{c}{\sqrt{KK_m}}=\frac{3.00\times10^{8}m/s}{(3.64)(5.18)}= 6.91\times10^{7}m/s $
b. $\lambda =\frac{v}{f}=\frac{6.91\times10^{7}m/s }{65.0Hz }= 1.06\times10^{6}m $.
c. $ B_{max}=\frac{E_{max}}{c}=1.04\times10^{-10}T $.
