University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 22 - Gauss's Law - Problems - Exercises - Page 745: 22.1

Answer

(a) $\Phi_{E} = 1.8 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}$ (b) Independent (c) (i) The largest value when $ \phi = 0 $ (ii) The smallest when $ \phi = 90^o$.

Work Step by Step

(a) The electric flux is calculated by \begin{align} \Phi_{E}& =E \cos \phi A\\ &=(14 \mathrm{N} / \mathrm{C})\left(\cos 60^{\circ}\right)\left(0.25 \mathrm{m}^{2}\right)\\ &=\boxed{1.8 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}} \end{align} (b) The electric field doesn't depend on the shape of the sheet as it is a flat sheet and the electric field is uniform over it. (c) (i) The largest value of $\Phi_{E}$ is when the angle $ \phi $ is zero where $\cos \phi = 1$ (ii) The smallest when the angle $ \phi $ is $90^o$ where $\cos \phi = 0$
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