Answer
(a) $a = 2440~m/s^2$
(b) $x = 1.10~m$
Work Step by Step
(a) $a = \frac{v-v_0}{t} = \frac{73.14~m/s}{0.0300~s}$
$a = 2440~m/s^2$
(b) $x = \frac{v^2-v_0^2}{2a} = \frac{(73.14~m/s)^2-0}{(2)(2440~m/s^2)}$ $x = 1.10~m$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 59: 2.22
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