Answer
(a) The time to accelerate to Mach 3 will be 20.3 seconds, which is longer than the 5.0 seconds which would cause the pilot to black out.
(b) The greatest speed the pilot can reach before he blacks out is 245 m/s.
Work Step by Step
(a) Mach 3 = (3)(331 m/s) = 993 m/s
$v = v_0 + at$
$t = \frac{v-v_0}{a} = \frac{993 ~m/s-0}{5g} = \frac{993 ~m/s}{(5)(9.80 ~m/s^2)}$
$t = 20.3$
The time to accelerate to Mach 3 will be 20.3 seconds, which is longer than the 5.0 seconds which would cause the pilot to black out.
(b) $v = v_0 + at = 0 + (5)(9.80 ~m/s^2)(5.0 ~s)$
$v = 245 ~m/s$
The greatest speed the pilot can reach before he blacks out is 245 m/s.
