Answer
$\omega = 5530~rad/s$
$T = 1.14\times 10^{-3}~s$
Work Step by Step
We can find the frequency.
$f = \frac{440~cycles}{0.5~s} = 880~Hz$
We can find the angular frequency.
$\omega = 2\pi~f$
$\omega = (2\pi)(880~Hz)$
$\omega = 5530~rad/s$
We can find the period.
$T = \frac{1}{f}$
$T = \frac{1}{880~Hz}$
$T = 1.14\times 10^{-3}~s$
