Answer
(a) $f = 0.0625~Hz$
(b) The amplitude is 10.0 cm
(c) The period is 16.0 seconds.
(d) $\omega = 0.393~rad/s$
Work Step by Step
(a) We can find the frequency.
$f = \frac{1~cycle}{16.0~s} = 0.0625~Hz$
(b) The object oscillates between -10.0 cm and 10.0 cm. Therefore, the amplitude is 10.0 cm.
(c) The object completes one cycle in 16.0 seconds. Therefore, the period is 16.0 seconds.
(d) We can find the angular frequency.
$\omega = 2\pi~f$
$\omega = (2\pi)(0.0625~Hz)$
$\omega = 0.393~rad/s$
