Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 9 - Linear Momentum and Collisions - Problems and Conceptual Exercises - Page 290: 23

Answer

$-0.519\frac{mm}{s}$

Work Step by Step

According to law of conservation of momentum $p_1x+p_2x=0$ $\implies m_bv_b+m_sv_s=0$ This can be rearranged as: $v_s=\frac{-m_bv_b}{m_s}$ We plug in the known values to obtain: $v_s=\frac{-(0.175)(14.1)}{4.75}$ $v_s=-0.519\frac{mm}{s}$
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