Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 9 - Linear Momentum and Collisions - Problems and Conceptual Exercises - Page 290: 10

Answer

a. The boulder's change in speed is less than the pebble's. b. Best: I

Work Step by Step

In terms of momentum, Newton's second law is $\displaystyle \sum\vec{\mathrm{F}}=\frac{\Delta\vec{\mathrm{p}}}{\Delta t} \qquad$9-3 The linear momentum of an object of mass $m$ moving with velocity $\vec{\mathrm{v}}$ is $\vec{\mathrm{p}}=m\vec{\mathrm{v}} \qquad $9-1 Linear momentum is a vector, pointing in the same direction as the velocity vector, $\vec{\mathrm{v}}$. $a.$ The same net force causes momentum change in both cases (9-3). $\Delta p_{1}=\Delta p_{2}\Rightarrow m\Delta v_{1}=m_{2}\Delta v_{2}$ $\displaystyle \frac{\Delta v_{1}}{\Delta v_{2}}=\frac{m_{2}}{m_{1}}=\frac{1}{m_{1}/m_{2}}$ The less massive object will experience a greater change of speed than the more massive object. The boulder's change in speed is less than the pebble's. $b.$ I: true II: the change in force results in change of momentum, not speed, so this is incorrect. III: yes, but it has no bearing on the question. Best: I
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