Answer
a) $y_f=0.942m$
b) no change
Work Step by Step
(a) We can find the required height as follows:
$K.E_i+U_i=K.E_i+U_f$
$\implies \frac{1}{2}mv_i^2+0=\frac{1}{2}mv_f^2+mgy_f$
This simplifies to:
$y_f=\frac{1}{2g}(v_i^2-v_f^2)$
We plug in the known values to obtain:
$y_f=\frac{(8.30)^2-(7.10)^2}{2(9.81)}$
$y_f=0.942m$
(b) The answer to part(a) will remain the same even if the mass is changed because the height change is independent of the mass.
