Answer
$-0.70J$
Work Step by Step
We can find the change in the gravitational potential energy as follows:
$\Delta y=Lcos\theta-L$
$\implies \Delta y=L(cos\theta-1)$
Now $\Delta U=mg\Delta y$
$\implies \Delta U=mgL(cos\theta-1)$
We plug in the known values to obtain:
$\Delta U=(0.33)(9.81)(1.2)(cos35^{\circ}-1)$
$\Delta U=-0.70J$
