Answer
$f_s=5.6KN$
Work Step by Step
The force exerted by static friction can be determined as
$f_s=F_c$ where $f_s$ is static friction and $F_c$ shows centripetal force
$\implies f_s=\frac{mv^2}{r}$
We plug in the known values to obtain:
$f_s=\frac{(1300)(16)}{59}$
$f_s=5.6KN$
