Answer
Order of increasing likelihood of skidding: $C,B,A$.
Work Step by Step
The magnitude of the centripetal force is equal to $$F=\frac{mv}{R^2}$$ Since mass and velocity are constant, as radius of curvature increases, the force decreases. So, the instant that has the largest radius of curvature would have the weakest centripetal force. The order of points ranked from smallest to largest radius of curvature is $C, B, A$. Therefore, since when radius of curvature increases, centripetal force decreases, the order of increasing likelihood that the car will slip is at points $C, B, A$.
