Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 179: 22

Answer

$k=8300N/m$

Work Step by Step

In the explanation, it can be concluded that the two forces present equal out. These are the spring force ($kx$) and the weight ($mg$). This means that $$mg=k\Delta x$$ Solving for $k$ yields $$k=\frac{mg}{\Delta x}$$ Substituting known values of $m=110. kg$, $\Delta x=13cm=0.13m$, and $g=9.80m/s^2$ yields a force constant of $$k=\frac{(110.kg)(9.80m/s^2)}{0.13m}=8300N/m$$
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