Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 179: 21

Answer

$k=2130N/m$

Work Step by Step

In the explanation, it can be concluded that the two forces present equal out. These are the spring force ($kx$) and the weight ($mg$). This means that $$mg=k\Delta x$$ Solving for $k$ yields $$k=\frac{mg}{\Delta x}$$ Substituting known values of $m=9.09kg$, $\Delta x=4.18cm=0.0418m$, and $g=9.80m/s^2$ yields a spring constant of $$k=\frac{(9.09kg)(9.80m/s^2)}{0.0418m}=2130N/m$$
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